Right now, I am working on the premise that there are two ciphers that overlap each other, and that neither use a polybius square but a simple alphabet count after a certain point.
"D'Agapeyeff Cipher" number series (original format)
75628 28591 62916 48164 91748 58464 74748 28483 81638 18174
74826 26475 83828 49175 74658 37575 75936 36565 81638 17585
75756 46282 92857 46382 75748 38165 81848 56485 64858 56382
72628 36281 81728 16463 75828 16483 63828 58163 63630 47481
91918 46385 84656 48565 62946 26285 91859 17491 72756 46575
71658 36264 74818 28462 82649 18193 65626 48484 91838 57491
81657 27483 83858 28364 62726 26562 83759 27263 82827 27283
82858 47582 81837 28462 82837 58164 75748 58162 92000
Further broken down into grid pairs with the last final three "0"s dropped:
75 62 82 85 91 62 91 64 81 64 91 74 85 84
64 74 74 82 84 83 81 63 81 81 74 74 82 62
64 75 83 82 84 91 75 74 65 83 75 75 75 93
63 65 65 81 63 81 75 85 75 75 64 62 82 92
85 74 63 82 75 74 83 81 65 81 84 85 64 85
64 85 85 63 82 72 62 83 62 81 81 72 81 64
63 75 82 81 64 83 63 82 85 81 63 63 63 04
74 81 91 91 84 63 85 84 65 64 85 65 62 94
62 62 85 91 85 91 74 91 72 75 64 65 75 71
65 83 62 64 74 81 82 84 62 82 64 91 81 93
65 62 64 84 84 91 83 85 74 91 81 65 72 74
83 83 85 82 83 64 62 72 62 65 62 83 75 92
72 63 82 82 72 72 83 82 85 84 75 82 81 83
72 84 62 82 83 75 81 64 75 74 85 81 62 92
Numbers in the "AB AB AB AB . . ." series (read from left to right, top to bottom) are then re-GROUPED as "AAAA . . . " and "BBBB . . ." for two, separate messages.
Cipher B: Numbers need to be re-divided again, and then read and copied backwards, after assigning their value on an "A to Z" 26 letter scale.
52 25 12 14 14 14 54 = [4 5-14-4 1-14 1-22-5 2-5] = D END AA DA WE BE
44 42 43 13 11 44 22 = [2-24 14 1 13 3 24 4 4 4] = BX N AMB DDDD
45 32 41 54 53 55 53 =
35 51 31 55 55 42 22 =
54 32 54 31 51 45 45 =
45 53 22 23 21 12 14 =
35 21 43 32 51 33 34 =
41 11 43 54 54 55 24 =
22 51 51 41 25 45 51 =
53 24 41 24 22 41 13 =
52 44 41 35 41 15 24 =
33 52 34 22 25 23 52 = [2-5 23
23 22 22 32 54 52 13 = [3-21-5 4 25 23 2-2 2-23] = CUE D Y X BB BX =
24 22 35 14 54 51 22 = [2-12-5-4 5 14-5-23-2 24] = B LED NEW BX
I will post more as it goes, but thought people might be interested in this new theory enough for me to ask for opinions.
